[Avcheck] Avcheck + avp + postfix = problem

Thu, 25 Apr 2002 07:00:32 +0200

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Hi all!

I guess I found the solution for my problem which I had described yesterday.
The problem was in line which was to start avcheck service from inside
postfix. I added a "-v" switch to every service triggered by incoming
message just to increase logging level. And then I noticed thah "pipe"
program had written something about "unknown flag q". So I removed the "q"
flag and now my avcheck line looks like this:
---
avcheck   unix -       n      n      -       5      pipe
    flags= user=avclient argv=/var/spool/avp/avcheck
    -d /var/spool/avp/./tst -s AVP:/var/spool/avp/ctl/AvpCtl
    -f ${sender} -S :1025 -- ${recipient}
---
(my man pipe says: "...flags=BFR.>" <-- There's no "q")

Without this "q" flag everything works as expected. But now I have the
question: what problems I can run into with configuration like this :') ?

Regards,

-- 
Grzegorz Meduna 

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<TITLE>RE: [Avcheck] Avcheck + avp + postfix =3D problem</TITLE>
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<P><FONT SIZE=3D2>Hi all!</FONT>
</P>

I guess I found the solution for my problem which I =
had described yesterday.
 The problem was in line which was to start avcheck =
service from inside postfix. I added a &quot;-v&quot; switch to every =
service triggered by incoming message just to increase logging level. =
And then I noticed thah &quot;pipe&quot; program had written something =
about &quot;unknown flag q&quot;. So I removed the &quot;q&quot; flag =
and now my avcheck line looks like this:

<P><FONT SIZE=3D2>---</FONT>
<BR><FONT SIZE=3D2>avcheck&nbsp;&nbsp; unix =
-&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; n&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; =
n&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; -&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; =
5&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; pipe</FONT>
<BR><FONT SIZE=3D2>&nbsp;&nbsp;&nbsp; flags=3D user=3Davclient =
argv=3D/var/spool/avp/avcheck</FONT>
<BR><FONT SIZE=3D2>&nbsp;&nbsp;&nbsp; -d /var/spool/avp/./tst -s =
AVP:/var/spool/avp/ctl/AvpCtl</FONT>
<BR><FONT SIZE=3D2>&nbsp;&nbsp;&nbsp; -f ${sender} -S :1025 -- =
${recipient}</FONT>
<BR><FONT SIZE=3D2>---</FONT>
<BR><FONT SIZE=3D2>(my man pipe says: &quot;...flags=3DBFR.&gt;&quot; =
&lt;-- There's no &quot;q&quot;)</FONT>
</P>

Without this &quot;q&quot; flag everything works as =
expected. But now I have the question: what problems I can run into =
with configuration like this :') ?

<P><FONT SIZE=3D2>Regards,</FONT>
</P>

<P><FONT SIZE=3D2>-- </FONT>
<BR><FONT SIZE=3D2>Grzegorz Meduna </FONT>
</P>

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